1.
Uji
Normalitas Kelas Eksperimen
Untuk menguji Normalitas maka perlu dilakukan
langkah-langkah sebagai berikut :
a.
H0 : sampel berasal dari
populasi yang berdistribusi normal
H1
: sampel tidak berasal dari populasi yang berdistribusi normal
b. α
= 0,05
c. statistik
uji yang digunakan
L
= Maks │F(Zi) - S(Zi)
│; dengan F(Zi) = P(Z ≤ Zi); Z ~ N(0,1); dan S(Zi) = proporsi cacah Z
≤ Zi terhadap seluruh Zi
d. Komputasi;
Tabel
Menncari Rata-Rata dan Standar Deviasi Kelas Eksperimen
|
X
|
f
|
fX
|
x
|
x2
|
fx2
|
|
62
|
2
|
124
|
-16.71
|
279.2241
|
558.4482
|
|
63
|
1
|
63
|
-15.71
|
246.8041
|
246.8041
|
|
67
|
1
|
67
|
-11.71
|
137.1241
|
137.1241
|
|
69
|
1
|
69
|
-9.71
|
94.2841
|
94.2841
|
|
70
|
2
|
140
|
-8.71
|
75.8641
|
151.7282
|
|
71
|
1
|
71
|
-7.71
|
59.4441
|
59.4441
|
|
72
|
1
|
72
|
-6.71
|
45.0241
|
45.0241
|
|
75
|
1
|
75
|
-3.71
|
13.7641
|
13.7641
|
|
77
|
3
|
231
|
-1.71
|
2.9241
|
8.7723
|
|
78
|
1
|
78
|
-0.71
|
0.5041
|
0.5041
|
|
81
|
2
|
162
|
2.29
|
5.2441
|
10.4882
|
|
82
|
1
|
82
|
3.29
|
10.8241
|
10.8241
|
|
83
|
1
|
83
|
4.29
|
18.4041
|
18.4041
|
|
84
|
1
|
84
|
5.29
|
27.9841
|
27.9841
|
|
85
|
4
|
340
|
6.29
|
39.5641
|
158.2564
|
|
86
|
2
|
172
|
7.29
|
53.1441
|
106.2882
|
|
87
|
1
|
87
|
8.29
|
68.7241
|
68.7241
|
|
89
|
1
|
89
|
10.29
|
105.8841
|
105.8841
|
|
90
|
1
|
90
|
11.29
|
127.4641
|
127.4641
|
|
91
|
2
|
182
|
12.29
|
151.0441
|
302.0882
|
|
Jumlah
|
30
|
2361
|
1563.242
|
2252.303
|
|
Rata-rata=78,7
 |
Standar
deviasi=8,66
 |
Tabel
Uji Normalitas Metode Liliefors
|
No
|
X
|
Zi
|
Fzi
|
Fkum
|
Szi
|
|Fzi-Szi|
|
|
1.
1
|
62
|
-1.93
|
0.0268
|
1
|
0.033333
|
0.006533
|
|
2.
|
62
|
-1.93
|
0.0268
|
2
|
0.066667
|
0.039867
|
|
3.
|
63
|
-1.81
|
0.0351
|
3
|
0.1
|
0.0649
|
|
4.
|
67
|
-1.35
|
0.0885
|
4
|
0.133333
|
0.044833
|
|
5.
|
69
|
-1.12
|
0.1314
|
5
|
0.166667
|
0.035267
|
|
6.
|
70
|
-1.01
|
0.1562
|
6
|
0.2
|
0.0438
|
|
7.
|
70
|
-1.01
|
0.1562
|
7
|
0.233333
|
0.077133
|
|
8.
|
71
|
-0.89
|
0.1867
|
8
|
0.266667
|
0.079967
|
|
9.
|
72
|
-0.77
|
0.2206
|
9
|
0.3
|
0.0794
|
|
10.
|
75
|
-0.43
|
0.3336
|
10
|
0.333333
|
0.000267
|
|
11.
|
77
|
-0.2
|
0.4207
|
11
|
0.366667
|
0.054033
|
|
12.
|
77
|
-0.2
|
0.4207
|
12
|
0.4
|
0.0207
|
|
13.
|
77
|
-0.2
|
0.4207
|
13
|
0.433333
|
0.012633
|
|
14.
|
78
|
-0.08
|
0.4681
|
14
|
0.466667
|
0.001433
|
|
15.
|
81
|
0.26
|
0.6026
|
15
|
0.5
|
0.1026
|
|
16.
|
81
|
0.26
|
0.6026
|
16
|
0.533333
|
0.069267
|
|
17.
|
82
|
0.38
|
0.648
|
17
|
0.566667
|
0.081333
|
|
18.
|
83
|
0.50
|
0.6915
|
18
|
0.6
|
0.0915
|
|
19.
|
84
|
0.61
|
0.7291
|
19
|
0.633333
|
0.095767
|
|
20.
|
85
|
0.73
|
0.7673
|
20
|
0.666667
|
0.100633
|
|
21.
|
85
|
0.73
|
0.7673
|
21
|
0.7
|
0.0673
|
|
22.
|
85
|
0.73
|
0.7673
|
22
|
0.733333
|
0.033967
|
|
23.
|
85
|
0.73
|
0.7673
|
23
|
0.766667
|
0.000633
|
|
24.
|
86
|
0.84
|
0.7995
|
24
|
0.8
|
0.0005
|
|
25.
|
86
|
0.84
|
0.7995
|
25
|
0.833333
|
0.033833
|
|
26.
|
87
|
0.96
|
0.8315
|
26
|
0.866667
|
0.035167
|
|
27.
|
89
|
1.19
|
0.883
|
27
|
0.9
|
0.017
|
|
28.
|
90
|
1.30
|
0.9032
|
28
|
0.933333
|
0.030133
|
|
29.
|
91
|
1.42
|
0.9222
|
29
|
0.966667
|
0.044467
|
|
30.
|
91
|
1.42
|
0.9222
|
30
|
1
|
0.0778
|
Dari tabel
diatas diperoleh; L = Maks │F(Zi) - S(Zi) │= 0,1318
e. Daerah
kritis
L0,05;29 ;=0,161 DK = {L│L > 0,161} Lobs = 0,1026 
DK
DK
f. Keputusan
uji H0 diterima
g. Kesimpulan
: sampel berasal dari populasi yang berdistribusi normal
2.
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